8511: BZOJ4511:[Usaco2016 Jan]Subsequences Summing to Sevens

Memory Limit:128 MB Time Limit:1 S
Judge Style:Text Compare Creator:
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Description

Farmer John's N cows are standing in a row, as they have a tendency to do from time to time. Each cow is labeled with a distinct integer ID number so FJ can tell them apart. FJ would like to take a photo of a contiguous group of cows but, due to a traumatic childhood incident involving the numbers 1…6, he only wants to take a picture of a group of cows if their IDs add up to a multiple of 7. Please help FJ determine the size of the largest group he can photograph. The first line of input contains N(1≤N≤50,000). The next N lines each contain the N integer IDs of the cows (all are in the range 0…1,000,000 ). 给定长度为N的数列A,求A最长的连续子序列,满足子序列中元素的和是7的倍数。输出最大的长度。如果不存在满 足条件的子序列,输出0。1 ≤ N ≤ 50000, 0 ≤ A_i ≤ 10 ^ 6


输入格式

Please output the number of cows in the largest consecutive group whose IDs sum to a multiple of 7. If no such group exists, output 0.


输出格式

You may want to note that the sum of the IDs of a large group of cows might be too large to fit into a standard 32-bit integer. If you are summing up large groups of IDs, you may therefore want to use a larger integer data type, like a 64-bit "long long" in C/C++.


样例输入

7
3
5
1
6
2
14
10

样例输出

5

In this example, 5+1+6+2+14 = 28. 

提示

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