301760: CF332D. Theft of Blueprints

Memory Limit:256 MB Time Limit:3 S
Judge Style:Text Compare Creator:
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Description

Theft of Blueprints

题意翻译

给一张 $n$ 个点的无向图,边有边权,且保证对于每个大小为 $k$ 的点的点集 $S$,都有且仅有一个点 $v$,使得 $S$ 中所有点与 $v$ 之间都存在一条边。 定义一个大小为 $k$ 的点集 $S$ 的权值为 $\sum_{u\in S}w(u,v)$,其中 $v$ 为每个集合对应的点,$w$ 为边权。 你的任务是求对于所有大小为 $k$ 的点集,他们的权值的平均值是多少,答案向下取整。 $2\le k < n\le 2000$ 翻译者:[逃离地球](https://www.luogu.com.cn/user/63951)

题目描述

Insurgents accidentally got hold of the plan of a top secret research polygon created on a distant planet for the needs of the Galaxy Empire. The insurgents suppose that this polygon is developing new deadly weapon. The polygon consists of $ n $ missile silos connected by bidirectional underground passages. The passages are linked to laboratories where research is conducted. Naturally, the passages are guarded severely: the passage between silos $ i $ and $ j $ is patrolled by $ c_{i,j} $ war droids. The insurgents studied the polygon plan and noticed its unusual structure. As it turned out, for any $ k $ -element set of silos $ S $ there is exactly one silo that is directly connected by a passage with each silo from $ S $ (we'll call this silo adjacent with $ S $ ). Having considered that, the insurgents decided to act as follows: 1. they choose a $ k $ -element set of silos $ S $ ; 2. a group of scouts lands from the air into each silo from $ S $ ; 3. each group moves along the corresponding passage to the silo, adjacent with $ S $ (as the scouts move, they check out the laboratories and watch for any signs of weapon blueprints); 4. in the silo, adjacent with $ S $ , the groups get on the ship and fly away. The danger of the operation is the total number of droids that patrol the passages through which the scouts will go. The danger of the operation obviously only depends on the way to choose set $ S $ . The insurgents haven't yet decided on the exact silos to send the scouts to. However, they already want to start preparing the weapons for the scout groups. To do that, the insurgents need to know the mathematical average of the dangers of the operations that correspond to all possible ways to choose set $ S $ . Solve this problem to help the insurgents protect the ideals of the Republic!

输入输出格式

输入格式


The first line contains two integers $ n $ and $ k $ ( $ 2<=n<=2000 $ , $ 1<=k<=n-1 $ ) — the number of silos and the number of scout groups, correspondingly. The next $ n-1 $ lines describe the polygon plan: the $ i $ -th of these lines contains $ n-i $ integers $ c_{i,i+1},c_{i,i+2},...,c_{i,n} $ — the number of droids that patrol the corresponding passages (- $ 1<=c_{i,j}<=10^{9} $ ; if $ c_{i,j}= $ - $ 1 $ , then silos $ i $ and $ j $ don't have a passage between them). All passages are bidirectional, that is, we can assume that $ c_{i,j}=c_{j,i} $ . No passages connect a silo with itself. It is guaranteed that the polygon plan meets the conditions of the problem statement.

输出格式


Print the average danger of the scouting operation, rounded down to an integer. Note that at the given limits the answer to the problem always fits into the standard integer 64-bit data type. Please do not use the %lld specifier to write 64-bit integers in С++. It is preferred to use the cout stream or the %I64d specifier.

输入输出样例

输入样例 #1

6 1
-1 -1 -1 8 -1
-1 5 -1 -1
-1 -1 3
-1 -1
-1

输出样例 #1

5

输入样例 #2

3 2
10 0
11

输出样例 #2

14

说明

In the first sample there are 6 one-element sets of silos. For sets $ {1} $ , $ {5} $ the operation danger will equal 8, for sets $ {3} $ , $ {6} $ — 3, for sets $ {2} $ , $ {4} $ — 5. The mathematical average equals ![](https://cdn.luogu.com.cn/upload/vjudge_pic/CF332D/6779180059bebd2b65884098cbd93497c7078b58.png). In the second sample there are 3 two-elements sets of silos: $ {1,3} $ (danger equals 21), $ {1,2} $ (danger equals 11), $ {2,3} $ (danger equals 10). The average operation danger equals ![](https://cdn.luogu.com.cn/upload/vjudge_pic/CF332D/e461096176a32afa0b41586e7192e319cef72429.png).

Input

题意翻译

给一张 $n$ 个点的无向图,边有边权,且保证对于每个大小为 $k$ 的点的点集 $S$,都有且仅有一个点 $v$,使得 $S$ 中所有点与 $v$ 之间都存在一条边。 定义一个大小为 $k$ 的点集 $S$ 的权值为 $\sum_{u\in S}w(u,v)$,其中 $v$ 为每个集合对应的点,$w$ 为边权。 你的任务是求对于所有大小为 $k$ 的点集,他们的权值的平均值是多少,答案向下取整。 $2\le k < n\le 2000$ 翻译者:[逃离地球](https://www.luogu.com.cn/user/63951)

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