102870: [AtCoder]ABC287 A - Majority

Problem Statement

There are $N$ people. Each of them agrees or disagrees with a proposal. Here, $N$ is an odd number.

The $i$-th $(i = 1, 2, \dots, N)$ person's opinion is represented by a string $S_i$: the person agrees if $S_i = $ For and disagrees if $S_i = $ Against.

Determine whether the majority agrees with the proposal.

Constraints

• $N$ is an odd number between $1$ and $99$, inclusive.
• $S_i = $ For or $S_i = $ Against, for all $i = 1, 2, \dots, N$.

Input

The input is given from Standard Input in the following format:

$N$
$S_1$
$S_2$
$\vdots$
$S_N$

Output

Print Yes if the majority of the $N$ people agree with the proposal; print No otherwise.

Sample Input 1

3
For
Against
For

Sample Output 1

Yes

The proposal is supported by two people, which is the majority, so Yes should be printed.

Sample Input 2

5
Against
Against
For
Against
For

Sample Output 2

No

The proposal is supported by two people, which is not the majority, so No should be printed.

Sample Input 3

1
For

Sample Output 3

Yes

问题描述

有$N$个人。他们每个人要么同意，要么反对一项提案。其中，$N$是一个奇数。

第$i$个（$i = 1, 2, \dots, N$）人的意见用字符串$S_i$表示：如果$S_i = $ For，则表示同意；如果$S_i = $ Against，则表示反对。

确定大多数人是否同意这项提案。

限制条件

• $N$是一个在$1$到$99$之间的奇数。
• 对于所有$i = 1, 2, \dots, N$，$S_i = $ For 或 $S_i = $ Against。

输入

输入以标准输入的以下格式给出：

$N$
$S_1$
$S_2$
$\vdots$
$S_N$

输出

如果$N$个人中的大多数同意提案，打印Yes；否则打印No。

样例输入1

3
For
Against
For

样例输出1

Yes

提案得到了两个人的支持，这是大多数，所以应该打印Yes。

样例输入2

5
Against
Against
For
Against
For

样例输出2

No

提案得到了两个人的支持，这不是大多数，所以应该打印No。

样例输入3

1
For

样例输出3

Yes