102490: [AtCoder]ABC249 A - Jogging

Memory Limit:256 MB Time Limit:2 S
Judge Style:Text Compare Creator:
Submit:0 Solved:0

Description

Score : $100$ points

Problem Statement

Takahashi and Aoki decided to jog.
Takahashi repeats the following: "walk at $B$ meters a second for $A$ seconds and take a rest for $C$ seconds."
Aoki repeats the following: "walk at $E$ meters a second for $D$ seconds and take a rest for $F$ seconds."
When $X$ seconds have passed since they simultaneously started to jog, which of Takahashi and Aoki goes ahead?

Constraints

  • $1 \leq A, B, C, D, E, F, X \leq 100$
  • All values in input are integers.

Input

Input is given from Standard Input in the following format:

$A$ $B$ $C$ $D$ $E$ $F$ $X$

Output

When $X$ seconds have passed since they simultaneously started to jog, if Takahashi goes ahead of Aoki, print Takahashi; if Aoki goes ahead of Takahashi, print Aoki; if they have advanced the same distance, print Draw.


Sample Input 1

4 3 3 6 2 5 10

Sample Output 1

Takahashi

During the first $10$ seconds after they started to jog, they move as follows.

  • Takahashi walks for $4$ seconds, takes a rest for $3$ seconds, and walks again for $3$ seconds. As a result, he advances a total of $(4 + 3) \times 3 = 21$ meters.
  • Aoki walks for $6$ seconds and takes a rest for $4$ seconds. As a result, he advances a total of $6 \times 2 = 12$ meters.

Since Takahashi goes ahead, Takahashi should be printed.


Sample Input 2

3 1 4 1 5 9 2

Sample Output 2

Aoki

Sample Input 3

1 1 1 1 1 1 1

Sample Output 3

Draw

Input

题意翻译

存在两个人散步。 前者速度 $ b $ 米每秒,每走 $ a $ 秒需要休息 $ c $ 秒。 后者速度 $ e $ 米每秒,每走 $ d $ 秒需要休息 $ f $ 秒。 求第 $ x $ 秒末时两者谁走的更远,前者更远输出 `Takahashi`,后者更远输出 `Aoki`,相同输出 `Draw`。

Output

分数:100分

问题描述

高桥和青木决定慢跑。
高桥重复以下动作:“以$B$米/秒的速度走$A$秒,然后休息$C$秒。”
青木重复以下动作:“以$E$米/秒的速度走$D$秒,然后休息$F$秒。”
当他们同时开始慢跑后经过$X$秒,高桥和青木中谁走得更远?

约束

  • $1 \leq A, B, C, D, E, F, X \leq 100$
  • 输入中的所有值都是整数。

输入

输入格式如下:

$A$ $B$ $C$ $D$ $E$ $F$ $X$

输出

当他们同时开始慢跑后经过$X$秒,如果高桥走在青木前面,输出Takahashi;如果青木走在高桥前面,输出Aoki;如果他们走了相同的距离,输出Draw


样例输入1

4 3 3 6 2 5 10

样例输出1

Takahashi

在他们开始慢跑后的前10秒,他们的行动如下:

  • 高桥走4秒,休息3秒,再走3秒。结果他总共走了$(4 + 3) \times 3 = 21$米。
  • 青木走6秒,休息4秒。结果他总共走了$6 \times 2 = 12$米。

因为高桥走在前面,应该输出Takahashi


样例输入2

3 1 4 1 5 9 2

样例输出2

Aoki

样例输入3

1 1 1 1 1 1 1

样例输出3

Draw

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