102034: [AtCoder]ABC203 E - White Pawn

Memory Limit:256 MB Time Limit:2 S
Judge Style:Text Compare Creator:
Submit:0 Solved:0

Description

Score : $500$ points

Problem Statement

Let $N$ be a positive integer. We have a $(2N+1)\times (2N+1)$ grid where rows are numbered $0$ through $2N$ and columns are also numbered $0$ through $2N$. Let $(i,j)$ denote the square at Row $i$ and Column $j$.

We have one white pawn, which is initially at $(0, N)$. Also, we have $M$ black pawns, the $i$-th of which is at $(X_i, Y_i)$.

When the white pawn is at $(i, j)$, you can do one of the following operations to move it:

  • If $0\leq i\leq 2N-1$, $0 \leq j\leq 2N$ hold and $(i+1,j)$ does not contain a black pawn, move the white pawn to $(i+1, j)$.
  • If $0\leq i\leq 2N-1$, $0 \leq j\leq 2N-1$ hold and $(i+1,j+1)$ does contain a black pawn, move the white pawn to $(i+1,j+1)$.
  • If $0\leq i\leq 2N-1$, $1 \leq j\leq 2N$ hold and $(i+1,j-1)$ does contain a black pawn, move the white pawn to $(i+1,j-1)$.

You cannot move the black pawns.

Find the number of integers $Y$ such that it is possible to have the white pawn at $(2N, Y)$ by repeating these operations.

Constraints

  • $1 \leq N \leq 10^9$
  • $0 \leq M \leq 2\times 10^5$
  • $1 \leq X_i \leq 2N$
  • $0 \leq Y_i \leq 2N$
  • $(X_i, Y_i) \neq (X_j, Y_j)$ $(i \neq j)$
  • All values in input are integers.

Input

Input is given from Standard Input in the following format:

$N$ $M$
$X_1$ $Y_1$
$:$
$X_M$ $Y_M$

Output

Print the answer.


Sample Input 1

2 4
1 1
1 2
2 0
4 2

Sample Output 1

3

We can move the white pawn to $(4,0)$, $(4,1)$, and $(4,2)$, as follows:

  • $(0,2)\to (1,1)\to (2,1)\to (3,1)\to (4,2)$
  • $(0,2)\to (1,1)\to (2,1)\to (3,1)\to (4,1)$
  • $(0,2)\to (1,1)\to (2,0)\to (3,0)\to (4,0)$

On the other hand, we cannot move it to $(4,3)$ or $(4,4)$. Thus, we should print $3$.


Sample Input 2

1 1
1 1

Sample Output 2

0

We cannot move the white pawn from $(0,1)$.

Input

题意翻译

一个 $(2n+1)\times(2n+1)$ 的棋盘上有 $m$ 个黑棋,你有一个白棋在 $(0,n)$。白棋在 $(i,j)$,每次可以对白棋进行一下操作: 1. 如果 $(i+1,j)$ **没有**黑棋,可以走到那。 2. 如果 $(i+1,j-1)$ **有**黑棋,可以走到那。 3. 如果 $(i+1,j+1)$ **有**黑棋,可以走到那。 不能走出棋盘。 问到 $2n+1$ 行时能到多少个点。

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