101855: [AtCoder]ABC185 F - Range Xor Query

Memory Limit:256 MB Time Limit:2 S
Judge Style:Text Compare Creator:
Submit:0 Solved:0

Description

Score : $600$ points

Problem Statement

We have an integer sequence $A$ of length $N$.
You will process $Q$ queries on this sequence. In the $i$-th query, given values $T_i$, $X_i$, and $Y_i$, do the following:

  • If $T_i = 1$, replace $A_{X_i}$ with $A_{X_i} \oplus Y_i$.
  • If $T_i = 2$, print $A_{X_i} \oplus A_{X_i + 1} \oplus A_{X_i + 2} \oplus \dots \oplus A_{Y_i}$.

Here, $a \oplus b$ denotes the bitwise XOR of $a$ and $b$.

What is bitwise XOR?

The bitwise XOR of integers $A$ and $B$, $A \oplus B$, is defined as follows:

  • When $A \oplus B$ is written in base two, the digit in the $2^k$'s place ($k \geq 0$) is $1$ if either $A$ or $B$, but not both, has $1$ in the $2^k$'s place, and $0$ otherwise.
For example, $3 \oplus 5 = 6$. (In base two: $011 \oplus 101 = 110$.)

Constraints

  • $1 \le N \le 300000$
  • $1 \le Q \le 300000$
  • $0 \le A_i \lt 2^{30}$
  • $T_i$ is $1$ or $2$.
  • If $T_i = 1$, then $1 \le X_i \le N$ and $0 \le Y_i \lt 2^{30}$.
  • If $T_i = 2$, then $1 \le X_i \le Y_i \le N$.
  • All values in input are integers.

Input

Input is given from Standard Input in the following format:

$N$ $Q$
$A_1 \hspace{7pt} A_2 \hspace{7pt} A_3 \hspace{5pt} \dots \hspace{5pt} A_N$
$T_1$ $X_1$ $Y_1$
$T_2$ $X_2$ $Y_2$
$T_3$ $X_3$ $Y_3$
$\hspace{22pt} \vdots$
$T_Q$ $X_Q$ $Y_Q$

Output

For each query with $T_i = 2$ in the order received, print the response in its own line.


Sample Input 1

3 4
1 2 3
2 1 3
2 2 3
1 2 3
2 2 3

Sample Output 1

0
1
2

In the first query, we print $1 \oplus 2 \oplus 3 = 0$.
In the second query, we print $2 \oplus 3 = 1$.
In the third query, we replace $A_2$ with $2 \oplus 3 = 1$.
In the fourth query, we print $1 \oplus 3 = 2$.


Sample Input 2

10 10
0 5 3 4 7 0 0 0 1 0
1 10 7
2 8 9
2 3 6
2 1 6
2 1 10
1 9 4
1 6 1
1 6 3
1 1 7
2 3 5

Sample Output 2

1
0
5
3
0

Input

题意翻译

维护序列 $A_1,A_2,\dots,A_n$。 $Q$ 次操作,每次给出 $T,X,Y$: - $T=1$:将 $A_X$ 替换为 $A_X \oplus Y$ - $T=2$:输出 $A_{X}\oplus A_{X+1}\oplus A_{X+2}\oplus\dots\oplus A_Y$。 其中 $\oplus$ 是按位异或。

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