101061: [AtCoder]ABC106 B - 105

Memory Limit:256 MB Time Limit:2 S
Judge Style:Text Compare Creator:
Submit:0 Solved:0

Description

Score: $200$ points

Problem Statement

The number $105$ is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between $1$ and $N$ (inclusive)?

Constraints

  • $N$ is an integer between $1$ and $200$ (inclusive).

Input

Input is given from Standard Input in the following format:

$N$

Output

Print the count.


Sample Input 1

105

Sample Output 1

1

Among the numbers between $1$ and $105$, the only number that is odd and has exactly eight divisors is $105$.


Sample Input 2

7

Sample Output 2

0

$1$ has one divisor. $3$, $5$ and $7$ are all prime and have two divisors. Thus, there is no number that satisfies the condition.

Input

题意翻译

## 题目描述 $105$是一个奇特的数。它虽然是一个奇数,却有八个因数。现在给定一个整数 $N$ ,请你求出在 $1$ 和 $N$ 之间有多少个奇数有八个因数? ## 输入格式 输入包括一个整数$N$。 ## 输出格式 输出在 $1$ 到 $N$ 之间 有八个因数的奇数个数。

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